Hi, I'm currently trying to work through a problem about calculating the most likely time for a hard disk to fail:(adsbygoogle = window.adsbygoogle || []).push({});

Hard disks fail with a probability per unit time: [itex]\alpha (t) = \alpha _0 t [/itex] where [itex]\alpha_0 = 0.5[/itex] years.

I know that the answer is [itex]t_{modal} = \frac{1}{\sqrt{\alpha_0}}[/itex], but am having problems deriving this. Here is what I've done so far:

The probability distribution can be calculated as follows:

[itex]f(x) = \alpha (t) e^{-\int \alpha (t) dt} = \alpha (t) e^{-\frac{1}{2} \alpha_0 t^2} [/itex]

The most likely time for the disk to fail will be when [itex]\frac{df}{dt} = 0 [/itex]. So when

[itex] 0 = -{\alpha_0}^2 t^2 e^{-\frac{1}{2} \alpha_0 t^2} [/itex]

This is where I get stuck. Is this the correct approach? Any ideas about how how I might proceed :)

Thanks

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Non Constant Hazard Rates - Calculating the modal failure rate of hard drive

Loading...

Similar Threads - Constant Hazard Rates | Date |
---|---|

B P → q with NOR operator and Constant F (false) | Jun 16, 2016 |

I Normal distribution and constant variance | Nov 9, 2015 |

Least squares of a constant | May 20, 2014 |

Weighted fit to a constant? | Jul 2, 2013 |

How to find limit of hazard function | Mar 1, 2013 |

**Physics Forums - The Fusion of Science and Community**