Non-Euclidean Physics & Straight Lines: Can They Coexist?

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Non-Euclidean modern physics does not eliminate the existence of straight lines; instead, it redefines them as "geodesics" within various geometrical frameworks. In non-Euclidean geometries, the properties of straight lines differ from those in Euclidean geometry, such as the existence of multiple parallel lines through a single point. The discussion emphasizes the importance of clearly defining what constitutes a "straight line" in different geometrical contexts. Riemannian Geometry is highlighted as a more encompassing term that includes both Euclidean and non-Euclidean geometries. Overall, the coexistence of straight lines and non-Euclidean physics is possible through these generalized concepts.
thinkandmull
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Here's something I've been wondering about: does non-Euclidean modern physics imply that there are no straight lines in our universe? If so, how is this possible? With any circular object or space, one can always draw a straight line through it, right? Thanks.
 
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What exactly do you mean by "non-Euclidean modern physics"? If you're thinking about the non-Euclidean space-time geometries of relativity, these allow straight lines.

It's also worth taking a few moments to crisply define what you mean by "straight line". If I present you with a path between points... What standards will you use to determine whether that path is a straight line?
 
No. It just means that straight lines - which are called 'geodesics' in Non-Euclidean geometries - don't necessarily have all the same properties that they have in Euclidean geometry.

For instance, in Euclidean geometry there is only one straight line through a point that is parallel to a line that doesn't pass through the point. In some non-Euclidean geometries there will be multiple such straight lines and in others there will be none.
 
Oh, so non-Euclidean ideas build of Euclidean ones?
 
In a sense. They are generalisations of them. Riemannian Geometry might be a better word than Non-Euclidean Geometry though, because Riemannian Geometries include both Euclidean and Non-Euclidean Geometries.
 
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