(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

There is a nonconducting rod of negligible thickness located along the x axis; its ends have coordinates x = 0 and x = L. It has a positive, nonuniform, linear charge density (lambda) = (alpha)x; alpha is constant. An infinite distance away, th eelectric potential is zero. Show that th electric potential at the location x=L+d is given by:

V=(alpha/4pi(epsilon_{0})) ((L+d) ln(1+L/d) -L)

2. Relevant equations

V= q/4pi epsilon r

3. The attempt at a solution

V = integral of dv

dv= dq/4pi(epsilon)r

dq=lambdadx

dq= alpha x dx

dV = ( (alpha) x dx) / (4 pi epsilon (d-x) )

V=constants <integral> xdx/ d-x <===== integration table

<integral> udu/a+bu = 1/b^{2}(a + bu - a*ln(a + bu) <evaluate from 0 to L>

when I evaluate i get:

(constants) * d-d-L d*ln( d / d - L )

and thats not what im supposed to get =/

ty

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# Homework Help: Nonconducting Rod electric pot.

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