Nonneg vs. Postive real numbers

AI Thread Summary
The discussion centers on the range of the function f(x) = e^(tanx) when the domain is restricted to the interval (-π/2, π/2). It is established that the range of tanx is all real numbers, and since e^(x) only yields positive values, the range of f(x) is positive reals. There is confusion regarding the distinction between positive reals and nonnegative reals, with positive reals defined as values greater than zero and nonnegative reals including zero. The answer sheet confirms that the correct answer is the set of positive reals, clarifying that since e^x can never be zero, the range does not include nonnegative reals. Thus, the function's range is indeed the set of all positive real numbers.
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Homework Statement


If the domain of f is restricted to the open interval (-pi/2,pi/2), then the range of f(x) = e^(tanx) is
A) the set of all reals
b the set of positive reals
c the set of nonnegative reals
d R: (0,1]
e none of these
(from barron's How to prep for ap calc)

Homework Equations


Above


The Attempt at a Solution


Range of tanx is all real numbers. The range for e^(x) for all real numbers is positive reals. The answers must be b or c

Conflict
The answer sheet states that b is the correct answer. How come? isn't b and c the same? What's the difference between all positive reals and all non negative reals?
 
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The positive reals are \{x\in \mathbb{R}:x>0\} whereas the nonnegative reals are \{x\in \mathbb{R}:x \not<0\}=\{x\in \mathbb{R}:x\geq 0\}. Since ex is never zero, then the range of the function is the positive reals.
 
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thanks a whole bunch
 
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