(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

an athlete releases a shot at an angle of 20 degrees and velocity of 16m/s.

What are the velocity and acceleration of the shot in terms of normal and tangential components when it is at the highest point of its trajectory?

What is the instantaneous radius of curvature of the shot's path when it is at the highest point of its trajectory?

2. Relevant equations

v = v*et = ds/dt*et

a = at*et + an*en

where at = dv/dt and an = v*dtheta/dt = v^2/rho

rho = (1 + (dy/dx)^2)^3/2 / |d^2y/dx^2|

3. The attempt at a solution

I'm having a hard time with understanding how to express the velocity and acceleration in terms of normal and tangential components...Is there even a normal component to velocity?This is what I'm thinking...When the shot reaches the highest point of its trajectory, the normal velocity would be 0m/s and its normal acceleration would be -9.8m/s^2. The tangential acceleration would be 0m/s^2 which would leave only the tangential velocity to be calculated... I calculated vt = vo*et = 16m/s*(cos20+sin20) = 20.5m/s. For the instantaneous rate of curvature rho = v^2/an = 20.5m/s / -9.8m/s^2 = -2.09m, which doesn't make any sense. Any help would be greatly appreciated

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Normal and tangential components

**Physics Forums | Science Articles, Homework Help, Discussion**