Normal force at the top of a loop the loop

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Homework Help Overview

The problem involves a car driving over a hill shaped as a circular arc, requiring the calculation of centripetal force and normal force at the top of the hill. The subject area pertains to dynamics and circular motion.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the centripetal force equation and questions the correctness of their approach for calculating the normal force. Some participants suggest reconsidering the equation used and recommend drawing a diagram for clarity.

Discussion Status

The discussion is ongoing, with participants providing feedback on the algebraic approach and identifying a sign error in the equation. There is no explicit consensus yet, but guidance has been offered regarding the formulation of the equations.

Contextual Notes

Participants are discussing the implications of the sign in the force equation and the need for a visual representation to aid understanding. The original poster has provided specific numerical values and results for part (a) of the problem.

BikeSmoth
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Homework Statement


A car drives over a hill that is shaped as a circular arc with radius 65.0 m. The car has a constant speed of 14.0 m/s and a mass of 423 kg. What is the magnitude of (a) the centripetal force on the car at the top of the hill and (b) the normal force exerted on the car by the road at this point?



Homework Equations


F=(mv^2)/r
(mv^2)/r=mg+N


The Attempt at a Solution


so i have answered (a) correctly with F=1275.5N, but I am not sure if I have the correct equation for (b) with the equation above I got N=-2869.9N
 
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You're algebra is good, so your numbers should be good too.
 
(mv^2)/r=mg+N

No,

[tex]m \frac{v^2}{r} = N - mg[/tex]

Try drawing a picture and the equation becomes clear.
 
Good catch, I didn't notice the wrong sign, my bad.
 

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