Solving for Normal Force in a 1k kg Car on a Dip

AI Thread Summary
To solve for the normal force acting on a 1,000 kg car at the bottom of a dip with a radius of 200 m and a speed of 10 m/s, the acceleration must first be calculated using the formula for centripetal acceleration, which is v²/r. This results in an acceleration of 0.5 m/s². The net force acting on the car is the sum of the normal force and the weight of the car, which must equal the centripetal force required to keep the car moving in a circular path. The normal force can be expressed as the weight of the car plus the centripetal force, leading to the equation N = mg + mv²/r. The correct magnitude of the normal force is determined to be 10,300 N.
briiannnaa04
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Homework Statement


a 1,000 kg car coasts into a slight dip in the road. The radius of the dip is 200-m. At the bottom of the dip the speed of the car is 10 m/s.
what is the magnitude and dirrection of the normal force?


Homework Equations


Sum of f=ma to find acceleration.


The Attempt at a Solution


the acceleration would be .5 m/s/s so wouldn't it just be .5*1000
the answer says it should be 10300 though.
 
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there is the normal force acting as well as weight. The resultant of these two provide the centripetal force, mv2/r
 
so what steps do i take first?
 
briiannnaa04 said:
so what steps do i take first?

Write down the resultant force in terms of the normal reaction and the weight
 

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