Calculating the Work Done by Normal Force on a Sliding Piano

In summary, A 330-kg piano slides 3.6 m down a 28º incline with an effective coefficient of kinetic friction of 0.40. A man is pushing back on it parallel to the incline to keep it from accelerating. The work done by the normal force is zero because the normal force is perpendicular to the direction of movement. This remains true even if there is acceleration in the horizontal direction.
  • #1
tica86
79
0
A 330-kg piano slides 3.6 m down a 28º incline and is kept from accelerating by a man who is pushing back on it parallel to the incline. The effective coefficient of kinetic friction is 0.40

what is the work done by the normal force?

If someone could let know how to find FN,

would it be mgcos28??
 
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  • #2
Workdone is F * distance.

Normal force as you said is mgcos28. But the distance is zero!
So no work is done by the normal force.
 
  • #3
your Fn is correct
 
  • #4
venkatg said:
Workdone is F * distance.

Normal force as you said is mgcos28. But the distance is zero!
So no work is done by the normal force.

Ok, I understand the definition of Work done but how do you know that the distance is zero?

Since the piano is sliding in the horizontal direction the 3.6 distance is horizontal and since normal force is vertical there is no distance??

If there was acceleration the net work done on the piano would NOT be 0 right?
 
  • #5
tica86 said:
Ok, I understand the definition of Work done but how do you know that the distance is zero?

Since the piano is sliding in the horizontal direction the 3.6 distance is horizontal and since normal force is vertical there is no distance??

If there was acceleration the net work done on the piano would NOT be 0 right?

Yes the the normal force does not cause any movement and so distance is zero.
This is the case even if there was acceleration in the horizontal direction (in this case along the incline)
 
  • #6
venkatg said:
Yes the the normal force does not cause any movement and so distance is zero.
This is the case even if there was acceleration in the horizontal direction (in this case along the incline)

Ok,thanks.
 

What is the definition of work done by normal force on a sliding piano?

The work done by normal force on a sliding piano refers to the force exerted by the surface on which the piano is sliding, perpendicular to the direction of motion. It is calculated by multiplying the magnitude of the normal force by the displacement of the piano in the direction of the force.

How do you calculate the normal force on a sliding piano?

The normal force on a sliding piano can be calculated by using the equation FN = mg cos θ, where m is the mass of the piano, g is the acceleration due to gravity, and θ is the angle of inclination of the surface on which the piano is sliding.

What is the relationship between work done and normal force on a sliding piano?

The work done by normal force on a sliding piano is directly proportional to the normal force applied and the displacement of the piano in the direction of the force. This means that the more force applied and the greater the displacement, the more work is done on the piano.

Can the work done by normal force on a sliding piano be negative?

Yes, the work done by normal force on a sliding piano can be negative if the angle of inclination of the surface is greater than 90 degrees. In this case, the normal force is acting in the opposite direction of the displacement, resulting in negative work being done.

What are some real-life examples of calculating the work done by normal force on a sliding piano?

One example is pushing a heavy box along a ramp. The normal force exerted by the ramp on the box is perpendicular to the ramp's surface and the direction of motion, and thus does work on the box. Another example is sliding furniture across a carpeted floor, where the normal force of the carpet on the furniture does work in the direction of motion.

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