- #1
Soniteflash
- 36
- 1
Homework Statement
During an extreme stunt, a 45 kg cheerleader stands on the shoulders of a 55 kg cheerleader, while riding in a transparent elevator with an upward acceleration of 2 m/s2. Find the normal force between the cheerleaders and between the elevator and the bottom cheerleader.
Homework Equations
F=ma
∑F=ma
The Attempt at a Solution
I drew a free body diagram first to identify all forces.
For the first part I came up with this equation:
∑F= Fn - mg = ma
∑F= Fn = mg + ma
∑F= Fn = m(g + a)
45 kg ( 9.81 + 2 )
= 531.45 N
= 531.45 N
For the second part I came up with this equation:
∑F= Fn - mg = ma
Fn = mg + ma
Fn = m (g + a)
100(11.8)
M of cheerleader 1 and 2: 45 kg + 55 kg =100
= 1181 N
Did I interpret the problem correctly? I always get confused when it comes to normal forces between two objects...M of cheerleader 1 and 2: 45 kg + 55 kg =100
= 1181 N