Normal Forces on a Ferris Wheel: Is the Top or Bottom Greater?

AI Thread Summary
In a Ferris wheel, a rider experiences different normal forces at the top and bottom of the circle due to centripetal acceleration. At the top, the normal force is less than the rider's weight, while at the bottom, the normal force is greater than the weight. Using Newton's 2nd Law, the equations confirm that the normal force at the bottom must counteract both the weight and provide the necessary centripetal force. Therefore, the normal force is indeed greater at the bottom than at the top. Understanding these forces is crucial for analyzing motion in vertical circular paths.
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Homework Statement


A Ferris wheel rider moves in a vertical circle of radius r at constant speed v. Therefore, he experiences a centripetal acceleration a.

Homework Equations


Is the normal force that the seat exerts on the rider at the top of the circle less than, more than, or the same as the normal force the the bottom of the ride?

Is the normal force equal to the weight?

Explain your answers using Newton's 2nd Law with centripetal acceleration.

Thank you!
 
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What are your thoughts on the question? Try drawing a free body diagram of the rider at both the top and bottom of the circle.
 
I drew my free body diagram- when the rider is on top, I have the normal force pointing up and weight and acceleration pointing down towards the center of the wheel.

When the rider is at the bottom, the normal force and acceleration are pointing up and the weight is pointing down.

For top-
F=m*a
-Fn+mg=m*a

For bottom-
F=m*a
Fn-mg=m*a

Is this right so far?
 
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So the normal force is greater at the bottom? Correct? Thanks!
 
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