Normal Forces on a Ferris Wheel: Is the Top or Bottom Greater?

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Homework Help Overview

The discussion revolves around the forces acting on a rider of a Ferris wheel as they move in a vertical circle. The focus is on comparing the normal forces experienced at the top and bottom of the ride, while considering centripetal acceleration and Newton's 2nd Law.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of free body diagrams to analyze forces at different positions on the Ferris wheel. Questions are raised about the relationship between normal force and weight at the top and bottom of the circle.

Discussion Status

Some participants confirm the reasoning presented in the free body diagrams and engage in a dialogue about the implications of their findings regarding the normal forces at different points in the ride.

Contextual Notes

The original poster seeks to understand the relationship between normal force and weight, as well as the application of Newton's 2nd Law in the context of centripetal motion.

Dannystu
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Homework Statement


A Ferris wheel rider moves in a vertical circle of radius r at constant speed v. Therefore, he experiences a centripetal acceleration a.

Homework Equations


Is the normal force that the seat exerts on the rider at the top of the circle less than, more than, or the same as the normal force the the bottom of the ride?

Is the normal force equal to the weight?

Explain your answers using Newton's 2nd Law with centripetal acceleration.

Thank you!
 
Last edited:
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What are your thoughts on the question? Try drawing a free body diagram of the rider at both the top and bottom of the circle.
 
I drew my free body diagram- when the rider is on top, I have the normal force pointing up and weight and acceleration pointing down towards the center of the wheel.

When the rider is at the bottom, the normal force and acceleration are pointing up and the weight is pointing down.

For top-
F=m*a
-Fn+mg=m*a

For bottom-
F=m*a
Fn-mg=m*a

Is this right so far?
 
Last edited:
So the normal force is greater at the bottom? Correct? Thanks!
 

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