(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The curve C has equation y = ln3x and crosses the x-axis at point (p,0)

The normal to the curve at the point Q with x-co-ordinate of q passes through the origin

Show that x=q is a solution of the equation x^{2}+ ln3x = 0

2. Relevant equations

3. The attempt at a solution

So, the gradient of ln(3x) at q is

1/q

therefore the gradient of the normal is -q

How do I go one from here?

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# Homework Help: Normal lines

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