Norton and Thevenin equivalents disagreement?

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There is a discrepancy in the calculated short-circuit current (Isc) when using Norton and Thevenin equivalents, with results showing 0.5mA for Norton and 2mA for Thevenin. The source labeled as Vx in the third diagram is incorrectly identified; it should be VCD, which serves as the reference voltage for the controlled voltage source. This misunderstanding leads to the differing results between the two methods. Clarifying the correct reference voltage resolves the issue. Accurate identification of components is crucial for consistent results in circuit analysis.
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When I solve for Isc through a and b using Norton and Thevenin equivalents between c and d I get different results. Why is that?

Norton =0.5mA
Thevenin =2mA
 
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In the third diagram, the source you've labelled as Vx is not the same as VCD. It's VCD which is the reference voltage for the controlled voltage source.
 
gneill said:
In the third diagram, the source you've labelled as Vx is not the same as VCD. It's VCD which is the reference voltage for the controlled voltage source.

Thank you so much! So that's where I went wrong...
 
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