Nortons Equivalent Circuit to find I

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SUMMARY

The discussion focuses on using Norton's Equivalent Circuit to determine the current (I) through a 15-ohm resistor in a complex circuit. Participants confirm that the 10-ohm and 5-ohm resistors should be treated as series components, as well as the 12-ohm and 16-ohm resistors. To find the Norton equivalent, users are advised to short the terminals A and B and calculate the current flowing through the short. Additionally, the equivalent resistance should be calculated by replacing the voltage source with a wire.

PREREQUISITES
  • Norton's Theorem
  • Basic circuit analysis techniques
  • Understanding of series and parallel resistor combinations
  • Ohm's Law (I = V/R)
NEXT STEPS
  • Study Norton's Theorem in detail
  • Practice circuit simplification techniques using source transformations
  • Learn to calculate equivalent resistance in complex circuits
  • Explore practical applications of Norton's and Thevenin's Theorems
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Electrical engineering students, circuit designers, and anyone looking to deepen their understanding of circuit analysis techniques, particularly in applying Norton's Theorem.

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Homework Statement


XNOoY.png


Use Norton's Equivalent Circuit to find current I through 15ohm resistor.

Homework Equations



norton's theorem states that any two terminal network that includes many sources and resistors can be converted into an equivalent two terminal network with one current source and a parallel resistor

The Attempt at a Solution



i have tried to simplify the circuit using source conversion but have failed. do i need to regard the 10 ohm and 5 ohm as in series and 12 ohm and 16 ohm in series? then use the resulting resistances in parallel to the 200v source?

any help on how to start would be great. thank you!
 
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The answer to your question is yes, think of it like this;

scan0002-1.jpg


Now remember, current will only flow in the virtical wire depending on the potential difference between the two points where it hits the horizontal ones, work out what the potential will be at the two points where the dividing wire touches the two parralel wires and then use I = V/R
 
Last edited:
Remove the 15-ohm resistor from the circuit and label the two nodes to which it connected A and B. What you want to do is replace the remaining circuit by its Norton equivalent. To find INorton, you want to short A and B and calculate how much current flows through the wire connecting A to B. To find RNorton, replace the voltage source with a wire and calculate the equivalent resistance seen between A and B.
 

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