- #1
Davorak
- 276
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Nuclear physics Pions and Parity? Ignore, nevermind
Why can:
<br /> \pi^- + d \rightarrow n + n + \pi^0<br />
not happen for pions at rest?
work so far:
<br /> \begin{array}<br /> {|c|c|c|c|c|c|}\hline&\pi^-&d&\rightarrow &n \ + \ n&\pi^0\\\hline{Spin}&0&1&\<br /> \rightarrow &1/2 \ 1/2&0\\\hline{J}&0&1&\rightarrow &L + \<br /> S&0\\\hline{Parity}&-1&1&\rightarrow &(-1)^{S+L+1}&-1\\\hline<br /> \end{array}<br />
d is deuterium
S+L for the nuetron pair must be even since they are identical fermions
Partity egeinvalues -1 != 1
I think the Paritiy inequality is the key, but i can not make the connection with a physical law.
Any help would be nice, Thanks
Edit: never mind I figuared it out. Aditional angular momentum on the left hand side will flip parity(l=1,3,5...), making parity conserved again. Thanks anyway
Why can:
<br /> \pi^- + d \rightarrow n + n + \pi^0<br />
not happen for pions at rest?
work so far:
<br /> \begin{array}<br /> {|c|c|c|c|c|c|}\hline&\pi^-&d&\rightarrow &n \ + \ n&\pi^0\\\hline{Spin}&0&1&\<br /> \rightarrow &1/2 \ 1/2&0\\\hline{J}&0&1&\rightarrow &L + \<br /> S&0\\\hline{Parity}&-1&1&\rightarrow &(-1)^{S+L+1}&-1\\\hline<br /> \end{array}<br />
d is deuterium
S+L for the nuetron pair must be even since they are identical fermions
Partity egeinvalues -1 != 1
I think the Paritiy inequality is the key, but i can not make the connection with a physical law.
Any help would be nice, Thanks
Edit: never mind I figuared it out. Aditional angular momentum on the left hand side will flip parity(l=1,3,5...), making parity conserved again. Thanks anyway
Last edited:
