1. The problem statement, all variables and given/known data How many terms has the G.p whose 2nd term is 1/2 and common ratio and the last term 1/4 and 1/128 respectiveley? From the question, it can be deduced that the common ratio, r =1/4 and the last term = 1/128 2. Relevant equations The Nt term of a G.p = arn-1 3. The attempt at a solution Given that r, the common ratio=1/4. T2, the second term is =1/2. Using the formula arn-1 where a = first term and r is = common ratio. Thus:T2=a(1/4)2-1 =1/2 a(1/4) = 1/2 a/4 = 1/2 2a = 4 a = 4/2 a = 2 Recall that Tn of G.p = arn-1 To find the Nt term, we need to put a, r and the last term in equation arn-1 = 1/128 2(1/4)n-1 =1/128 I multiplied through by 1/2 2 * 1/2(1/4)n-1 = 1/128 * 1/2 (1/4)n-1 = 1/256 I don't know how to deal with the power n-1 in other to procceed further and arive at the answer.