Number Theory Euclidean Algorithm

MathSquareRoo
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Homework Statement



Suppose that u, v ∈ Z and (u,v) = 1. If u | n and v | n, show that uv | n. Show that this is false if (u,v) ≠ 1.

Homework Equations



a | b if b=ac

3. The Attempt at a Solution

I understand this putting in numbers for u,v, and n but I don't know how to formally write it.
 
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Do you know a relation between the gcd and linear combinations of u and v?
 
Linear combination of u and v are equal to the gcd correct? And the gcd divides u and v I believe. I need help organizing all these ideas.
 
MathSquareRoo said:
Linear combination of u and v are equal to the gcd correct?
Not necessarily true for an arbitrary linear combination, but there exists at least one linear combination equal to the gcd.

And the gcd divides u and v I believe.
Certainly, gcd means greatest common divisor, so it's certainly a divisor.

OK, if we let d = the gcd, then you know there is a linear combination such that d = au + bv. Now you know that u divides n and v divides n, so how can you use that fact here?
 
So then au divides n and vb divides n?
 
MathSquareRoo said:
So then au divides n and vb divides n?

No, that isn't necessarily true. However, if u divides n, then n = ur for some integer r. And v divides n, so n = vs for some integer s. Now try using these facts.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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