Observing galaxies: area of sky would I need to survey

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SUMMARY

The discussion focuses on calculating the area of the sky required to survey in order to find 100 Elliptical galaxies using a garden telescope with a magnitude limit of 14. By applying the distance formula d=100.2(m-M-25) with m=14 and M=-21, the distance d is determined to be 100 Mpc. This results in a total observable volume of 4/3⋅π⋅d³, equating to approximately 4,188,790 Mpc³. To find the necessary solid angle, the volume needed to observe (10,000 Mpc³) is divided by the total volume, yielding a fraction of 2.39⋅10-3, which is then multiplied by 4π to express it as a solid angle.

PREREQUISITES
  • Understanding of astronomical concepts such as absolute magnitude and apparent magnitude.
  • Familiarity with volume calculations in three-dimensional space.
  • Knowledge of the formula for number density (n=N/V).
  • Basic grasp of solid angles and their relation to spherical volumes.
NEXT STEPS
  • Research the implications of absolute magnitude on galaxy visibility.
  • Learn about the calculation of solid angles in astrophysics.
  • Explore the use of different telescopes and their magnitude limits for galaxy observation.
  • Investigate the distribution of Elliptical galaxies in the universe and their density variations.
USEFUL FOR

Astronomy students, amateur astronomers, astrophysicists, and anyone interested in galaxy surveys and observational techniques in astronomy.

Cedric Chia
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Homework Statement


Given that there are 10-2 Ellipticals per Mpc3 and my garden telescope can reach to 14 mag. How large an area of sky would I need to survey to find 100 Elliptical galaxies ? (assume the typical absolute magnitude for an Elliptical galaxy is -21 mag).

Homework Equations


d=100.2(m-M-25)
n=N/V

The Attempt at a Solution


by substituting m=14 and M=-21 into the first equation I found d=100Mpc,

which indicates the volume of sky I could possibly observed is 4/3⋅π⋅d3 = 4188790 Mpc3,

using the second equation n=N/V , where n=number density, I have 10-2 = 100/V,

thus V=10000Mpc3, which is the volume I need to observed to find 100 galaxies.

with these values, how can I find how large the area of sky I need to survey?
 
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Cedric Chia said:

Homework Statement


Given that there are 10-2 Ellipticals per Mpc3 and my garden telescope can reach to 14 mag. How large an area of sky would I need to survey to find 100 Elliptical galaxies ? (assume the typical absolute magnitude for an Elliptical galaxy is -21 mag).

Homework Equations


d=100.2(m-M-25)
n=N/V

The Attempt at a Solution


by substituting m=14 and M=-21 into the first equation I found d=100Mpc,

which indicates the volume of sky I could possibly observed is 4/3⋅π⋅d3 = 4188790 Mpc3,

using the second equation n=N/V , where n=number density, I have 10-2 = 100/V,

thus V=10000Mpc3, which is the volume I need to observed to find 100 galaxies.

with these values, how can I find how large the area of sky I need to survey?
You have almost finished... What units are you going to use to report your answer (solid angle, fraction of the hemisphere sphere...)?
 
hutchphd said:
You have almost finished... What units are you going to use to report your answer (solid angle, fraction of the hemisphere sphere...)?
How can I find solid angle relative to the 10000MPc3?
 
Cedric Chia said:
How can I find solid angle relative to the 10000MPc3?
The solid angle for a whole sphere is 4pi...for half sphere 2pi...how much of the sphere do you need to view?
 
hutchphd said:
The solid angle for a whole sphere is 4pi...for half sphere 2pi...how much of the sphere do you need to view?
Thank you for the quick reply,

the total volume of the sphere is 4188790 Mpc3
("which indicates the volume of sky I could possibly observed is 4/3⋅π⋅d3 = 4188790 Mpc3")

and the volume I need to view is 10000Mpc3
("thus V=10000Mpc3, which is the volume I need to observed to find 100 galaxies")

with these values how can I find solid angle?
 
What fraction of the total sphere volume do you need to observe?
 
hutchphd said:
What fraction of the total sphere volume do you need to observe?
I think that would be (volume I need to observe) / (total sphere volume) = (10000) / (4188790) = 2.39⋅10-3
 

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