Odd Parity of States: 2p m=0, 2p m=1, 26f m=0, 2s

[Mattofix]

Homework Statement

Which of the following states have odd parity?

a. 2p m=0
b. 2p m=1
c. 26f m=0
d. 2s

The Attempt at a Solution

Knowing the wavefunctions for a,b, and d, i think that all of them have odd parity. What about the 26f m=0 state?

 

[gabbagabbahey]

I'd recommend you write down the values of n, m and \ell for each of those orbitals, and then use those to deduce the form of each wavefunction, and then see what happens to each one under the parity transformation.

\psi_{n\ell m}(r,\vartheta,\varphi) \propto e^{- \rho / 2} \rho^{\ell} L_{n-\ell-1}^{2\ell+1}(\rho) \cdot Y_{\ell}^{m}(\vartheta, \varphi )