One-D Kinematic Question w/ rising hot air balloon

AI Thread Summary
The problem involves a hot-air balloon rising at a constant speed of 2.3 m/s while a camera is tossed upward at an initial speed of 14 m/s from the ground. The key confusion arises regarding the acceleration of the balloon and the camera; the balloon has zero acceleration since it is moving at a constant rate, while the camera experiences gravitational acceleration of -9.8 m/s². To find the height of the passenger when the camera reaches her, one must set the equations of motion for both the balloon and the camera equal to each other. The discussion clarifies that the balloon's constant speed means it does not accelerate, which is crucial for solving the problem correctly. Understanding these concepts is essential for determining the correct time and height when the camera reaches the passenger.
millergc
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Homework Statement



A hot-air balloon has just lifted off and is rising at a constant rate of 2.3m/s. Suddenly, one of the passengers realizes she has left her camera on the ground. A friend picks it up and tosses it straight upward with an initial speed of 14m/s.

If the passenger is 2.5m above her friend when the camera is tossed, how high is she when the camera reaches her.


Homework Equations



Constant linear acceleration equations

v=v(i) +a*t
x=x(i) + v(i)t + 1/2at^2


The Attempt at a Solution



The part of this problem that confuses me is the acceleration of the camera. I know that the acceleration of the balloon is just -9.8 but how can I find the acceleration of the camera without time, etc. I tried solving where x(balloon)= x(camera) but i used -9.8 as the acceleration for both and i do not believe i got the right time.

Any help would be great.
Thanks.
 
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millergc said:
The part of this problem that confuses me is the acceleration of the camera.
The acceleration of the camera is the same as any other body in free fall.
I know that the acceleration of the balloon is just -9.8
No. You are told that the balloon is rising at a constant rate--so what must be its acceleration?
 
Doc Al said:
The acceleration of the camera is the same as any other body in free fall.

No. You are told that the balloon is rising at a constant rate--so what must be its acceleration?

zero, ok i understand, i just thought -g would still act on the balloon but it wouldn't

Thanks
 
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