One-Dimensional Gravitational Motion

AI Thread Summary
The discussion focuses on calculating the height from which a ball is released, given its mass and the time it takes to reach the ground. The key equations involved are F=MA and Vo=h/t - 0.5at. Participants clarify that since the ball is released from rest, the initial velocity (Vo) is zero. The contributor attempts to solve the equation but expresses uncertainty about the correctness of their calculations. The conversation emphasizes understanding the implications of initial conditions in kinematic equations.
BMWPower06
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Homework Statement


It takes 2.70 s for a small ball with a mass of 0.050 kg released from rest from a tall building to reach the ground. Calculate the height from which the ball is released.


Homework Equations


F=MA
Vo=h/t - .5at


The Attempt at a Solution



I plugged in all the knowns into the above equation but was still left with an unknown initial V and an unknown height. unsure how to proceed.
 
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BMWPower06 said:

Homework Statement


It takes 2.70 s for a small ball with a mass of 0.050 kg released from rest from a tall building to reach the ground. Calculate the height from which the ball is released.


Homework Equations


F=MA
Vo=h/t - .5at


The Attempt at a Solution



I plugged in all the knowns into the above equation but was still left with an unknown initial V and an unknown height. unsure how to proceed.

Well, the problem says the ball was released from rest. What does this imply about the initial V?
 
CaptainZappo said:
Well, the problem says the ball was released from rest. What does this imply about the initial V?

o ok it is zero, is the rest of my equation correct?
 
Last edited:
so I've got:
0= h/2.7 +13.23
 
It looks right to me.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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