One-dimensional Gravitational motion

AI Thread Summary
To calculate the height from which a ball is released in one-dimensional gravitational motion, the time of fall and gravitational acceleration are essential. For a ball falling for 2.80 seconds, the height can be determined using the equation h = 0.5 * g * t², where g is the acceleration due to gravity. If the same ball were released from the same height on the moon, the time to hit the ground would differ due to the moon's lower gravitational acceleration. Users are encouraged to research free fall equations and concepts to better understand the calculations involved. Engaging with resources like Hyper Physics can provide valuable insights for beginners in physics.
nycjay222
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A) It takes 2.80 s for a small ball with a mass of 0.040 kg released from rest from a tall building to reach the ground. Calculate the height from which the ball is released.

B)If that ball had been released from the same height, but this time above the surface of the moon, how long would it have taken for the ball to hit the ground?
 
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Hi nycjay222,
Welcome to PF.
How much you know about the free fall?
Can you find out the relevant equations for free fall?
 
i really don't know anything this is my first encounter with physics and my ta is behind and I haven't learned much to do these which is why I am so stranded !
 
Have you got any textbook?
Go to Hyper Physics site and collect the required information.
 

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