- #1

TG3

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- 0

## Homework Statement

A .3 kg ball is compressed a maximum of 0.6 cm when it strikes the floor at 9.29 m/s. Assuming acceleration is constant, what is the force the ball exerts on the floor?

## Homework Equations

vf^2 = v0^2 + 2A(x-x0)

Once I find A it will be easy, since

F=MA

## The Attempt at a Solution

0^2 = 9.29^2 + 2A (.006)

0 = 86.3041 + .012 A

-86.3041= .012A

-7192= A

F=MA

F=.3 (-7192)

F= -2157