One more quick convervation of energy problem

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The skier's problem involves calculating the height of a slope using energy conservation principles, where potential energy (PE) equals the change in kinetic energy (KE). The initial speed is 5 m/s and the final speed at the bottom is 13 m/s. The correct formula for height is derived from the equation h = (vi^2 - vf^2) / (2g). The initial attempt incorrectly included mass terms, leading to confusion in calculations. The correct height of the slope is determined to be 7.3 meters, highlighting the importance of accurately applying energy conservation equations.
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Homework Statement



A skier leaves a slope with an initial speed of 5 m/s. Her speed at the bottom of the slope is 13 m/s. What is the height of the slope?

Homework Equations


PE= mgh
KE= 1/2mv^2


The Attempt at a Solution



PE + KE1 = KE2

PE=KE2-KE1

mgh = 1/2mv^2 -1/2mv^2

gh = 1/2v^2 -1/2v^2

h = 1/2mv^2 -1/2mv^2 / g

when I plug everything in, I get 14.9

the answer is 7.3


what am I doing wrong?
 
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crimsonn said:
h = 1/2mv^2 -1/2mv^2 / g
Where have these masses appeared from? If these masses are just a typo and you really used,

h = (vi2 - vf2)/(2g)

Then you have simply plugged the numbers in wrong.
 
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