Op Amp Subtractor, Integrator, Differentiator & Inverter Uses

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Op amp subtractors, integrators, differentiators, and inverters have various practical applications in electronics. Subtractors can function as comparators, which are useful for signal processing. Integrators are often used as low-pass filters, while differentiators serve as high-pass filters, enhancing signal processing capabilities. Active filters, which incorporate op amps, offer advantages over passive filters due to their amplification properties. Understanding these applications is essential for measuring phase differences in signals, such as using an integrator to derive DC voltage proportional to the phase difference between square waves.
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What are the practical uses of op amp subtractor, integrator, differentiator, inverter?

One I know that of op amp adder is that they can be used as audio mixer .
 
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Hyperspace2 said:
What are the practical uses of op amp subtractor, integrator, differentiator, inverter?

One I know that of op amp adder is that they can be used as audio mixer .

Good thought on the adder/mixer. What would be some uses that you can think of for the other opamp building blocks that you mention?
 
Technically a comparator is a type of subtractor. Consider it a subtractor with a very very very very very very very large gain. Not too hard to think of uses for a comparator.
 
Integrator == low pass filter
Differentiator == high pass filter
Inverter == Tea Party Filter... just kidding, sorry...
 
schip666! said:
Inverter == Tea Party Filter... just kidding, sorry...

:smile:
 
Averagesupernova said:
Technically a comparator is a type of subtractor. Consider it a subtractor with a very very very very very very very large gain. Not too hard to think of uses for a comparator.
Ok I got it.
schip666! said:
Integrator == low pass filter
Differentiator == high pass filter
Inverter == Tea Party Filter... just kidding, sorry...
Yeah, I also came to learn about the low pass filter and high pass filter too. But I think of them now as a independent circuit elements . Aren't they just combination of Resisitor and capacitors? I don't think they need op amp. Active High pass filter are just the combination of filter and op amp for High pass filter and amplification respectively. Similar in the case of the active low pass filter. Amn't I correct?
 
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An active filter has advantages over a passive. Have you done the math and made some comparisons?
 
Something I've recently worked with using an integrator. Perhaps might be of help.

The goal is to measure phase between two square waves. If you feed the two signals into a XOR gate, then one can show that the output will have different width or delta t which is directly proportional to a phase between the square waves.

The output looks something like this:

[PLAIN]http://www.pcsilencioso.com/cpemma/graphics/swave.gif


The wider the signal, the more phase difference there is. Now, what you want to do is to get DC voltage output that is proportional to the phase difference, and all you have is this rectangular pulse wave. How would you recover the width?

The answer is with an integrator. We known that the amplitude is constant. If you integrate this rectangular pulse wave, then you get the area under the rectangle which is (Amplitude * Delta t) and the delta t is the width you are after which is proportional to phase difference.
 
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Averagesupernova said:
An active filter has advantages over a passive. Have you done the math and made some comparisons?
No I haven't tried it yet. I would like to look at it now.
waht said:
Something I've recently worked with using an integrator. Perhaps might be of help.

The goal is to measure phase between two square waves. If you feed the two signals into a XOR gate, then one can show that the output will have different width or delta t which is directly proportional to a phase between the square waves.

The output looks something like this:

[PLAIN]http://www.pcsilencioso.com/cpemma/graphics/swave.gif


The wider the signal, the more phase difference there is. Now, what you want to do is to get DC voltage output that is proportional to the phase difference, and all you have is this rectangular pulse wave. How would you recover the width?

The answer is with an integrator. We known that the amplitude is constant. If you integrate this rectangular pulse wave, then you get the area under the rectangle which is (Amplitude * Delta t) and the delta t is the width you are after which is proportional to phase difference.

Thanks for sharing . I am the begineer . I have to go long way ahead to view yours. I think you have many things for sharing.
 
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