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Rudinhoob
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Did you think it is impossible to use op-amps in cases where there is no connection available to the Earth such as in airplanes, cars/trucks, and portable devices?
It is important to understand that the ground point in a circuit is just an arbitrary point in a circuit, where we DECIDE that the potential (voltage) is zero.
Now, if you connect to batteries is series (- + - +), and choose the ground point to be the connection between them you will find that you've created a bipolar source.
Simply take your eraser and remove that wire between the three-line "Ground" symbol and the junction of your natteries. In fact, erase the "Ground" symbol too.How can I achieve the same result without grounding?
Yes.Rudinhoob said:Is the inverting configuration on the left valid?
What makes it different than the one on the right?
Rudinhoob said:Are you referring to "reference node"? If so then this has no physical impact on circuit it's merely used for calculations.
Not sure what do you mean by "bipolar source" I thought every source is bipolar with + and - poles.
Yes, that's the way to do it, basically.Rudinhoob said:Is the inverting configuration on the left valid? What makes it different than the one on the right?
You could view it as a single power supply with a centre tap. http://physicsforums.bernhardtmediall.netdna-cdn.com/images/icons/icon6.gifRudinhoob said:But how using two power sources is different than using one? Cannot just combine both into one source?
No, a bipolar source means a source where one terminal has a potential lower than ground (i.e. it has three terminals: plus, ground and minus).
Rudinhoob said:And the ground of this "bipolar" battery has to be connected to "ground" or "earth"? or can be connected to what point in the circuit?
Rudinhoob said:And the ground of this "bipolar" battery has to be connected to "ground" or "earth"? or can be connected to what point in the circuit?
The diagram on the right cannot work. There really is no feedback path. It appears that there is, but when the inverting input is pulled in a direction by the resistor network coming from the output, there is nothing that is keeping the non-inverting input from following it by the same amount. The non-inverting input needs to be 'held' to something as it is in the schematic on the left.
Can you see any DC feedback which would keep the output at mid rail? If you can't see it then you have to assume it's not there and you have to provide your own. If it had some vestigial bias, it could be either way.Rudinhoob said:Then how could you tell the circuit on the right does not have "real" negative feedback?
The LM386 for example is a small audio amp that can work withpout DC feedback..
But it's not a general purpose opamp instead it's made for AC signals. So its designers removed the need for DC feedback.
Rudinhoob said:Then this DC feedback is OpAmp type dependent, which means it has to do with the internal circuitry. Although not necessarily exposed in the analysis, it seems that there are some decisions that are dependent on this and to justify them, we need to include the details of the OpAmp in analysis.
Why are you looking for loopholes here?
jim hardy said:... these old National appnotes were great. TI has re-issued most of them
http://www.ti.com/lit/an/snla140a/snla140a.pdf
Yea, it's copyrighted and can't be reproduced without permission from Analog Devices. Good info to have on hand though.jim hardy said:first one in that series, bottom of pp 1.7 is a note that applies to this thread. I would post an excerpt but it appears to disallow copy & paste.
The circuit in question's noninverting input voltage is undefined, or 'indeterminate'.
So right hand circuit suffers more from an undefined input than from lack of feedback.
Averagesupernova said:There is no AC feedback concerning the circuit in question either.
There is no AC feedback concerning the circuit in question either.
I guess that's true.