Open cover which has no finite subcover

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Homework Statement



Give an example of an open cover in R^n which has no finite subcover.

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The Attempt at a Solution



{x ε Q | x < sqrt(3)} U {x ε Q | x > sqrt(3) }
 
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None of the elements in that set is an open subset of Rn. None of them are even subsets of Rn!


Or... were you trying to say that you wanted to consider an open cover whose elements are the two sets
{x ε Q | x < sqrt(3)} and {x ε Q | x > sqrt(3) }​
? If so, you need to show four things:

(1) Those two sets are subsets of Rn
(2) Those two sets are open
(3) Those two sets cover Rn
(4) No finite subcover covers the same space as the entire cover does
 
n/m. I've figured this out.
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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