Operations with Linear Transformations

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Homework Statement



Let T:U \rightarrow V be a linear transformation, and let U be finite-dimensional. Prove that if dim(U) > dim(V), then Range(T) = V is not possible.

Homework Equations



dim(U) = rank(T) + nullity(T)

The Attempt at a Solution



I almost think there must be a typo in the book. For instance, let U be P4 (the space of polynomials degree 4 and lower), and let V be P2. Let T be the second derivative operator. Then the Range of T is V. This example is even printed earlier in the same book that I got this question from.

Otherwise, I see no reason why the Range(T) couldn't be V. The rank(T) could at most be dim(V), but that is no problem, because the nullity(T) could be anywhere from dim(U) to dim(U)-dim(V).

So, is this a typo? Or (maybe more likely) am I missing something obvious?
 
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Let T:U \rightarrow V be a linear transformation, and let U be finite-dimensional. Prove that if dim(U) > dim(V), then Range(T) = V is not possible.

Definitely a typo. It should be <.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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