Solve Optics Problem: Diameter of Star Imaged w/ 18" Telescope

eluru
Messages
2
Reaction score
1
Optics Problem( pleasez help me)

Consider a telescope with an aperture of 18 inches and focal length of 120 inches.
what is the diameter of the star imaged in focal plane of telescope? Take the image diameter to be associated with the first minimum in the diffraction pattern of the image. Use wavelength of 550nm.

Hint: By Using lens diffraction theory.
 
  • Like
Likes Jaadu06
Physics news on Phys.org


What is the equation for diffraction at a circular aperture?
 


hiiiiiiii friend.,

for the circular aperture

U= C exp(ikr) * integral of Exp(ikysin@) 2sqrt(R^2-Y^2) dy
bet ween the limits (-R,R)
 
Last edited:


The nice Mr Rayleigh solved it for you
 


In other words 1.22 times wavelength divided by aperture diameter for the half angular width of the central maxima.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?

Similar threads

Replies
7
Views
1K
Replies
2
Views
1K
Replies
9
Views
2K
Replies
1
Views
2K
Replies
3
Views
1K
Replies
1
Views
3K
Replies
7
Views
4K
Replies
4
Views
2K
Back
Top