Optics question: What two positions of a lens gives a sharp image?

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Homework Help Overview

The discussion revolves around the placement of a +4.5 D thin lens between a lamp and a screen that are 1m apart, with the goal of producing a sharp image on the screen. Participants explore the conditions under which a sharp image can be formed and the implications of using Gauss's law in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply Gauss's law to determine the lens positions but expresses confusion about how to find the two possible positions for a sharp image. Some participants question the validity of the law being referenced and seek clarification on the focal points.

Discussion Status

Participants are actively engaging with the problem, with some providing corrections and clarifications regarding the application of Gauss's law. There is a sense of progress as one participant indicates they have arrived at a solution, though the discussion remains open to further exploration of the concepts involved.

Contextual Notes

There is mention of potential confusion regarding the law used and the definitions of focal points, indicating that assumptions about the lens setup may need further examination.

LeeLoo
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1. A lamp and a screen are 1m apart and a +4.5 D thin lens is mounted between them. Where must the lens be placed in order to produce a sharp image on the screen, and what will be the magnification?



2. Gauss Law: L' = L + F



3. I attempted this question by using the Gauss Law but I just don't know how to find the two possible positions of the lens to give a sharp image. I thought that a sharp image might be formed at F or F' but it doesn't work. Can someone please show me how to do this problem and explain it :)
 
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LeeLoo said:
I thought that a sharp image might be formed at F or F' but it doesn't work.
Why doesn't it work? What do you know about "F" ?
 
Welcome to PF!

LeeLoo said:
Gauss Law: L' = L + F

Hi LeeLoo! Welcome to PF! :smile:

I don't think that's the right law …

shouldn't it have 1/… ? :wink:
 
Oh, yeah, the law is actually n/l + F = n'/l' but i thought people could abbreviate it like that. anyway, yay, i know how to do the question now!

1/l' + 1/l = F
l' +l =1m
l' = 1 - l

so sub that in and get two answers for 'l' which are the lens positions :D

and magnification= l'/l so you get m = -2 or -1/2

COOL!
 

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