Optics, the resulting power of the lens .?

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A thin lens with a refractive index of 1.5 has a front surface power of +11 diopters and a back surface power of -6 diopters. When submerged in a liquid with a refractive index of 1.6, the resulting power of the lens changes due to the surrounding medium. Participants in the discussion seek to determine the new power of the lens and request relevant equations and guidance on how to approach the problem. The options provided for the resulting power are -1 diopter, +1 diopter, -5 diopters, and +5 diopters. Clarification on the calculations and reasoning behind the answer is emphasized as urgent.
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optics, the resulting power of the lens...??

a thin lens , made of refractive index 1.5,has a front surface +11 d power and back surface -6d ..if this lens is submerged in a liquid of refractive index 1.6, the resulting power of the lens is...

a)-1 dioptre

b)+1 dioptre

c)-5 dioptre

d)+5 dioptre

pleasezzz answer ,,,and why please ..its emergency:frown:..
 
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hi mero coactail! welcome to pf! :wink:
mero coactail said:
a thin lens , made of refractive index 1.5,has a front surface +11 d power and back surface -6d ..if this lens is submerged in a liquid of refractive index 1.6, the resulting power of the lens is...

a)-1 dioptre

b)+1 dioptre

c)-5 dioptre

d)+5 dioptre

pleasezzz answer ,,,and why please ..its emergency:frown:..

what equations are relevant here?

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 

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