- #1

lagwagon555

- 60

- 1

## Homework Statement

Consider the intersection of two surfaces: an elliptic paraboloid

z = x2 + 2x + 4y2 and a right circular cylinder x2 + y2 = 1. Use Lagrange multipliers to find

the highest and lowest points on the curve of intersection

## The Attempt at a Solution

L = x^2 + 2x + 4y^2 - λ(x^2 + y^2 - 1)

Lx = 2x + 2 - 2λx = 0

Ly = 8y - 2λy = 0

Rearranging gives the bizzare result of λ = 4. Aren't I supposed to be able to eliminate the lagrange multipliers by it giving me λ in terms of y? It's giving me a value instead.

I ran with this anyway, and got the answer of x = 1/3, y = +-0.94, but I don't think this is correct. I suspect I'm doing something wrong algebraically? Any help hugely appreciated :)