Optimizing Paraboloid Bounds for Triple Integral

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Homework Statement


Evaluate the triple integral xdV where E is the solid bounded by the paraboloid x= 2y^2 + 2z^2 and x=2.

The Attempt at a Solution


The bounds I got are

for z

-sqrt(1-y^2) <= y <= sqrt(1-y^2)

for y

-1 <= y <= 1

for x

2y^2 + 2z^2 <= x <= 2

are these correct?
 
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\iiint{2y^2+2z^2\leq x\leq 2}xdV= \iint_{y^2+z^2\leq 1}\int_{2y^2+2z^2}^{2}x\,dxdA
 
Im sorry I don't quite understand what you have written, can you please explain if possible?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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