- #1
alexteplyaxins
- 3
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- Homework Statement
- Determine the largest internal shear force resisted by the bolt.
- Relevant Equations
- Apply equibrilium state.
Optimizing Shear Stress in Structural Analysis
- Thread starter alexteplyaxins
- Start date
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- Tags
- Shear Shear stress Stress
AI Thread Summary
The discussion revolves around optimizing shear stress in structural analysis through the application of force and momentum equilibrium. The first case can be solved to determine forces F_a and F_b, but the second case lacks sufficient information for a complete analysis. It is noted that removing visible forces could still result in shear on the bolt due to tensions and compressions in adjacent members. An approach suggested involves treating one of the left-side forces as an unknown to express shear values in relation to it. The conversation emphasizes the need for more details to effectively analyze case b.
- #2
osilmag
Gold Member
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What are the sums of the forces for each case?
- #3
alexteplyaxins
- 3
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I just can solve problem ##a## by apply equilibrium of force and momentum to find ##F_a## and ##F_b##. But with case b, I can't find third equation.osilmag said:
Thank for read
- #4
alexteplyaxins
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Boom, boom !
- #5
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Yes, b) is not fully specified. E.g. you could take away all of the shown forces and still have shear on the bolt resulting from tensions and compressions in the members on the left.alexteplyaxins said:
You could set one of those on the left as an unknown and find the shears in terms of that, then find the value of the unknown which minimises the maximum shear.
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19.
For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Let's declare that for the cylinder,
mass = M = 10 kg
Radius = R = 4 m
For the wall and the floor,
Friction coeff = ##\mu## = 0.5
For the hanging mass,
mass = m = 11 kg
First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on.
Force on the hanging mass
$$mg - T = ma$$
Force(Cylinder) on y
$$N_f + f_w - Mg = 0$$
Force(Cylinder) on x
$$T + f_f - N_w = Ma$$
There's also...
This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is
The second part of the problem is exactly why you get this affect.
And one more spoiler:
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