- #1
Edwardo_Elric
- 101
- 0
Homework Statement
Obtain the general solution:
[tex](1 - x)y' = y^2[/tex]
Homework Equations
The Attempt at a Solution
[tex](1 - x)\frac{dy}{dx} = y^2[/tex]
[tex](1 - x)dy = y^2dx[/tex]
[tex]\frac{dy}{y^2} = \frac{dx}{(1-x)}[/tex]
integrating both sides:
i used ln on the constant at the right side
[tex]-\frac{1}{y} = \ln(1 - x) + \ln{c}[/tex]
so my answer is:
[tex]-1 = y\ln{(c(1 - x))}[/tex]
the answer seems to be different at the back of my book w/c is
[tex] 1 = y\ln{(c(1 - x))}[/tex] <<< no negative as before
can you tell me what's wrong with my soln?