Orthogonality of Associated Laguerre Polynomial

Muh. Fauzi M.
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I have a problem when trying to proof orthogonality of associated Laguerre polynomial. I substitute Rodrigue's form of associated Laguerre polynomial :

upload_2015-3-17_17-49-19.png

to mutual orthogonality equation :

upload_2015-3-17_17-49-40.png

and set, first for
upload_2015-3-17_17-50-7.png
and second for
upload_2015-3-17_17-50-20.png
.

But after some step, I get trouble with this stuff :

upload_2015-3-17_17-50-31.png

I've already search solution for this form but still no light. Any body here could help?
 
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The best way is using the differential equation. Write it for ## L^k_n ## and ## L^k_m ##. Then multiply the first by ## L^k_m## and the second by ## L^k_n ##. Then subtract one from the other. Come back if you encounter a problem!
 
Last edited:
Shyan said:
The best way is using the differential equation. Write it for ## L^k_n ## and ## L^k_m ##. Then multiply the first by ## L^k_m## and the second by ## L^k_n ##. Then subtract one from the other. Come back if you encounter a problem!
Well I still didn't get it. ## L^k_n ## has a rodrigues form and also associated Laguerre polynomial. Which one I need to use?
 
Muh. Fauzi M. said:
Well I still didn't get it. ## L^k_n ## has a rodrigues form and also associated Laguerre polynomial. Which one I need to use?
I said the differential equation, which is:
## x \frac{d^2 L_n^{k}}{dx^2} +(k+1-x) \frac{dL_n^{k}}{dx} +n L_n^k =0##
 
Shyan said:
I said the differential equation, which is:
## x \frac{d^2 L_n^{k}}{dx^2} +(k+1-x) \frac{dL_n^{k}}{dx} +n L_n^k =0##
Nah... I got it. But still, I am stuck when connecting it with the orthogonality...
 
Muh. Fauzi M. said:
Nah... I got it. But still, I am stuck when connecting it with the orthogonality...
I explained it in that post! Just write the equation two times for ## L_m^k ## and ## L_n^k##. Then multiply the first by ## L_n^k## and the second by ## L_m^k ## and subtract one from the other. Then find an integrating factor and multiply the equation by it. You'll find out how to continue but come back if you didn't.
 
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