Orthonormal Set spanning the subspace (polynomials)

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Homework Help Overview

The discussion centers on proving that a specific set of functions forms an orthonormal set spanning the same subspace as a given set of polynomials in the context of real polynomials with a defined inner product. The functions in question are y0(t) = 1, y1(t) = sqrt(3)(2t-1), and y2(t) = sqrt(5)(6t^2-6t+1), compared to the polynomials xn(t) = tn for n = 0, 1, 2.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of Legendre Polynomials Rules to establish the basis for the functions. There is an inquiry into the orthogonality and orthonormality of the proposed functions, as well as whether they span the same space as the original set of polynomials.

Discussion Status

The discussion is ongoing, with participants exploring the necessary integrals to demonstrate orthonormality and questioning the definitions and properties of the polynomials involved. There is no explicit consensus yet, but several lines of reasoning are being examined.

Contextual Notes

Participants are considering the implications of proving orthogonality and orthonormality, as well as the specific integrals required to establish these properties. There is also a focus on the subspace spanned by the original polynomials and the implications of the definitions used.

Cassi
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Homework Statement


In the linear space of all real polynomials with inner product (x, y) = integral (0 to 1)(x(t)y(t))dt, let xn(t) = tn for n = 0, 1, 2,... Prove that the functions y0(t) = 1, y1(t) = sqrt(3)(2t-1), and y2 = sqrt(5)(6t2-6t+1) form an orthonormal set spanning the same subspace as {x0, x1, x2}.

Homework Equations

The Attempt at a Solution


I was attempting to use the Legendre Polynomials Rules to show that these polynomials form the basis but when I devise the Legendre Polynomials, they are different than those given.
 
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Cassi said:

Homework Statement


In the linear space of all real polynomials with inner product (x, y) = integral (0 to 1)(x(t)y(t))dt, let xn(t) = tn for n = 0, 1, 2,... Prove that the functions y0(t) = 1, y1(t) = sqrt(3)(2t-1), and y2 = sqrt(5)(6t2-6t+1) form an orthonormal set spanning the same subspace as {x0, x1, x2}.

Homework Equations

The Attempt at a Solution


I was attempting to use the Legendre Polynomials Rules to show that these polynomials form the basis but when I devise the Legendre Polynomials, they are different than those given.

What's stopping you? Can you prove they are orthogonal? Orthonormal? Span the same space?
 
What are the "Legendre Polynomials Rules"?
 
So x_0= 1, x_1= t, and x_2= t^2. What subspace do those span?

y_0(t) = 1, y_1(t) = \sqrt{3}(2t-1), and y_2 = \sqrt{5}(6t^2-6t+1). Show that these span the same subspace as the above. To show that they are orthonormal (which would also show that they are independent) you need to do 6 integrals.

For example, \int_0^1 (y_0(t))^2 dt must be equal to 1 while \int_0^1 y_0y_1 dt must be equal to 0.
 

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