Oscillating mechanical systems. find maximum velocity and acceleration ?

AI Thread Summary
The discussion revolves around calculating the maximum velocity and acceleration of a mass-spring system. A mass of 0.3 kg is suspended from a spring with a stiffness of 200 N/m and displaced by 10 mm. The amplitude is confirmed to be 0.01 m, leading to calculations of maximum velocity at 0.2582 m/s and maximum acceleration at 6.6667 m/s² using the formulas for oscillating systems. Participants also discuss the mass required to double the maximum velocity, with varying answers suggesting either 0.075 kg or 0.15 kg based on different calculations of angular frequency. The conversation highlights the importance of verifying calculations and understanding the principles of oscillating mechanical systems.
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Oscillating mechanical systems. find maximum velocity and acceleration !?

A mass of 0.3 kg is suspended from a spring of stiffness 200 N m–1. If the mass is displaced by 10 mm from its equilibrium position and released, for the resulting vibration

A) Calculate maximum velocity
B) Calculate maximum acceleration

I need help with this please, for starters is the amplitude 0.01m?

Thanks
 
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Yes, amplitude is correct, you must have had some training :smile:. Welcome to PF. There are a ton of googleable resources out there. Check them out, give the problem a try and come back with some specific questions.
 


Ok thanks

I think I've got it now

using:-

v=- ωA sin(ωt - φ)
a= - ω2A cos(ωt - φ)

And the maximums occur when sin(ωt - φ)=1 and cos(ωt - φ)=1

Thanks again!
 


omega = square root (k/m) = 25.82

a) 0.001 x 25.82 x 1 = 0.2582 m/s

b)0.001 x 25.82^2 x 1 = 6.6667 m/s^2

Anybody care to have a go at the last question:-

d) the mass required to produce double the maximum velocity
calculated in (b) using the same spring and initial deflection

I get an answer of 0.075kg

Thanks
 
bensm0 said:
omega = square root (k/m) = 25.82

a) 0.001 x 25.82 x 1 = 0.2582 m/s

b)0.001 x 25.82^2 x 1 = 6.6667 m/s^2

Anybody care to have a go at the last question:-

d) the mass required to produce double the maximum velocity
calculated in (b) using the same spring and initial deflection

I get an answer of 0.075kg

Thanks

would this not be 0.15kg?

ω = √k/m = 200/0.15 = 36.51

b)0.001 x 36.51^2 x 1 = 13.33 m/s^2 = double Vmax

I know this is a late response to a question but i have the same question and want to check my working.

(thanks in advance)
 
Eddievic,

I got the same answers as bensm0,

If you double the answer that you got in a) 0.5164
use that in your equations and transpose for mass.

i think :)
 
justadaftspark said:
Eddievic,

I got the same answers as bensm0,

If you double the answer that you got in a) 0.5164
use that in your equations and transpose for mass.

i think :)

I believe you are correct my paper came back and mine was incorrect the paper was an overall pass though so I have not investigated it fully.
 
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