Oscillations of a Balanced Object

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SUMMARY

The discussion centers on the calculations related to the oscillations of a balanced object, specifically focusing on the distance from the pivot to the center of mass, which was determined to be sqrt(2) L/4. The moment of inertia was initially calculated as 1/6mL^2 + 2m(L/2)^2, which was simplified to 2/3mL^2. The participant encountered an error in their calculations, mistakenly multiplying the gravitational force term (2mgd) by 4 instead of 2, leading to an incorrect final result. After correcting this mistake, they arrived at the correct answer.

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Homework Statement
Two identical thin rods, each of mass m and length L, are joined at right angles to form an L-shaped object. This object is balanced on top of a sharp edge. If the object is displaced slightly, it oscillates. Find ω, the angular frequency of oscillation of the object.
Relevant Equations
ω=Sqrt(mgd/I)
I calculated that the distance from the pivot to the center of mass was sqrt(2) L/4, and that the moment of inertia was 1/6mL^2+2m(L/2)^2. I simplified the moment of inertia to 2/3mL^2, and the 2mgd to sqrt(2)mgL. Cancelling out the m's and the L's, I end up with sqrt(3sqrt(2)g/2L). It says that this is incorrect, however, and I'm not sure why. Any help is appreciated.
 
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I figured it out myself, haha. I was accidentally multiplying the mgd by 4 instead of 2. I got the right answer.
 

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