Oscillations of a weighted ruler

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When a weighted ruler oscillates and the weights fall off, the angular frequency decreases due to the reduced mass, resulting in an increased period of oscillation. The amplitude, contrary to initial assumptions, increases because the maximum displacement of the ruler becomes greater after the weights are removed. This phenomenon aligns with the principles of simple harmonic motion, where amplitude is defined by maximum displacement. The discussion emphasizes the relationship between mass, angular frequency, period, and amplitude in oscillatory motion. Understanding these dynamics is crucial for analyzing the behavior of oscillating systems.
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Hi everyone. Can you imagine a metre rule attached to a tabletop and weights are attached at the other end? The ruler will sag. The ruler is then given a push to let it oscillate. However the weights fell off when it is oscillating. So what is the effect on period and amplitude?

I did:

Since w=sqrt of k/m, when m decreases w decreases.
w=2pi/t, thus t will increase.

However, although i cannot think of any equation that affects the amplitude (I think it is constant), but my answer script says that amplitude actually increased. Can anyone use equations to prove that to me?

Thank you!
 
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The equation that affects the amplitude is the equation of simple harmonic motion. This equation states that the amplitude of the oscillation is equal to the maximum displacement of the particle. Since the weights had fallen off, the maximum displacement will increase leading to an increase in the amplitude.
 
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