Othogonal complement of a span

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SUMMARY

The discussion centers on proving that the orthogonal complement of the span of a set \( S \), denoted as \( \langle S \rangle^{\bot} \), is equal to the orthogonal complement of \( S \), denoted as \( S^{\bot} \). The user successfully demonstrated that \( S^{\bot} \subseteq \langle S \rangle^{\bot} \) and sought clarification on proving the reverse inclusion. The argument presented shows that if \( y \in \langle S \rangle^{\bot} \), then \( y \) is orthogonal to all vectors in \( S \), confirming \( \langle S \rangle^{\bot} \subseteq S^{\bot} \) is valid.

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Homework Statement


Show that <S>^{\bot}=S^{\bot}

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The Attempt at a Solution


I manage to show S^{\bot}\subseteq<S>^{\bot}.
What about the other way round? Any way of proving without using the concept of basis?
 
Last edited:
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You need to prove that span(S)^{\bot} is a subset of S^{\bot}. However, you know that S \subseteq span(S). So, given the latter, try to prove the former.
 
Last edited:
This is what I come out with:

Let y\in<S>^{\bot}, then <y,w>=0, for all w\in<S>.
But S\subseteq<S>.
Hence for y\in<S>^{\bot}, then <y,w>=0, for all w\inS.
Hence y\inS^{\bot}.
Hence <S>^{\bot}\subseteqS^{\bot}.

Is it correct? Or should I say "for some w"?
 

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