Outside the origin circular loop current density

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SUMMARY

The discussion focuses on deriving the current density for a circular loop displaced along the y-axis in spherical coordinates. The correct expression for the current density is given as \mathbf{J}=I\delta(\theta-\frac{\pi}{2})\frac{\delta(r-a)}{a}\hat{\phi}, which satisfies the integral condition I=\int\mathbf{J}\cdot{d\mathbf{S}}. The user is advised to translate the origin-centered solution for a circle of radius a to Cartesian coordinates, apply a displacement, and then convert back to spherical coordinates to obtain the desired current path.

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Mr. Rho
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Hi, I'm trying to write the current density for such circular loop in spherical coordinates. For a circular loop of radius a that lies in the XY plane at the origin, the current density it's simply:

\mathbf{J}= \frac{I}{2\pi\sin\theta}\delta(\theta-\frac{\pi}{2})\frac{\delta(r-a)}{a}\hat{\phi}​

I want the current density of the circular loop of radius a displaced a distance c towards the y axis.

Any suggestions?
 
Last edited:
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I can't make sense of this. Your units don't balance. What is the relationship between a, c, and r? Could you try again?
 
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stedwards said:
I can't make sense of this. Your units don't balance. What is the relationship between a, c, and r? Could you try again?
Sorry I wrote the equation wrong, just fixed it. I'm using this kind of spherical coordinates:

250px-Spherical_polar.png
 
No, really. Think about it a bit and restate the entire question. 'cuse, now current and current density have the same units, and nobody knows what ##c## is. I'd sleep on it.
 
stedwards said:
No, really. Think about it a bit and restate the entire question. 'cuse, now current and current density have the same units, and nobody knows what ##c## is. I'd sleep on it.

I don't know what I was thinking, the correct current density is:

\mathbf{J}=I\delta(\theta-\frac{\pi}{2})\frac{\delta(r-a)}{a}\hat{\phi} = I\sin\theta\delta(\cos\theta)\frac{\delta(r-a)}{a}\hat{\phi}​

it satisfies I=\int\mathbf{J}\cdot{d\mathbf{S}}=\int_{0}^{\pi}\int_{0}^{\infty}\mathbf{J}\cdot{\hat{\phi}}rdrd\theta, where \mathbf{S} is a surface perpendicular to the current direction.

Sorry for not making myself clear for what I'm asking. I hope this image makes things clear:

Untitled.png
The current density I present is case (i) and the current density I need is case (ii).
 
To begin with, take the origin-centered solution for a circle of radius ##a##, change to Cartesian coordinates, translate to the right (##x \leftarrow x' = x + c##), then back to spherical coordinates.

It will give the equation for the current path you want.
 
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