When Will the Thrown Mass Overtake the Dropped Shot Put in Freefall?

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To determine when the thrown mass overtakes the dropped shot put, the equations of motion for both objects must be set up. The shot put is dropped from 60m, while the 100g mass is thrown down from 70m at 10 m/s. Since mass does not affect freefall, both objects are influenced solely by gravity, which is 9.8 m/s². The position equations for both objects can be equated to find the time at which they occupy the same position. Solving these equations will yield the time of intersection.
yakiland
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Heres a question I am really stuck on...

Homework Statement


If Person A drops a shot put weighing 1.5 kg from a height of 60m, and at exactly the same time Person B throws down a 100g mass at a speed of 10 m/s from 70m up, at what time would the mass overtake the shot put?


Homework Equations


mass is irrelevant due to freefall.

to find the total time it takes for each item to reach the ground, i used
x=(v+u/2)*t
AND
v^2=u^2+2ax

acceleration due to gravity=9.8m/s^2

The Attempt at a Solution


I have no idea where to start...
 
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If you write out the x equations for both the A ball and B ball, then you can equate the two and find the time they occupy the same position.
 

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