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phy21050
How is velocity independent of mass, specifically when talking about the Conservation of Mechanical Energy. Thanks for your time.
Ow is velocity independent of mass
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Velocity is independent of mass in the context of the Conservation of Mechanical Energy because the potential energy lost by a mass as it moves down an incline is converted into kinetic energy, which depends on the square of the velocity. This principle holds true regardless of the masses involved, as long as no external forces act on the system. In a collision scenario where mass m1 moves down an incline and collides with mass m2, the velocity of m1 just before the collision is determined by its initial height and the acceleration due to gravity, not its mass. If m1 is greater than m2, the conservation of momentum and energy principles still apply, and the final velocities post-collision will depend on the masses and initial velocities, but the initial velocity of m1 remains independent of its mass.
Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance)
My thoughts for the first case , one of them must be 12 volt while the other is 0
The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Here is what I tried
This question was actually asked in one of our engineering entrances.
The answer was 1D.
My teachers say that we have to use μₘ/fₘ to get to this answer. I cannot understand why. I'll be really glad if you could tell me the exact definition of power (numerically) that works in all scenarios.
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