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Parallel-axis theorem

  1. Nov 25, 2007 #1
    1. The problem statement, all variables and given/known data
    If I have a solid sphere (I = (2/5)MR^2) and it rotates around a point on an axis that is 5m away (it has radius 0.1m) - is the moment of inertia then: I = (2/5)MR^2 + M*(4.9m)^2?

    My question is - does the parallel-axis only work when we are moving the axis of rotation around "inside" the body or also outside it?
     
  2. jcsd
  3. Nov 25, 2007 #2

    Doc Al

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    Staff: Mentor

    It works inside or outside. I'd say that I = (2/5)MR^2 + M*D^2, where D is the distance from the center of mass to the desired axis.
     
  4. Nov 25, 2007 #3
    Of course, my bad - but thanks again. You have helped me very much.
     
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