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Parametric equations

  1. Apr 30, 2012 #1
    I am having difficulty finding the lenght of the curve represented by parametric equations. The difficulty comes from not knowing how to determine if the curve transverses once, twice,... in a given interval.

    The only solution I can think of is (say x = g(t) and y = f(t) and y = F(x) on interval [a,b] )
    Look at graph x = g(t) and determine on the interval [a,b] if there are any values of x that repeat
    If so then the graph y = F(x) on [a,b] may transverse more than once,
    next look at the graph y = f(x) and determine if and y values repeat.

    Then from these values one should be able to determine if the graph y =F(x) overlaps its self... but I know there must be a better method...
    Help please.
     
  2. jcsd
  3. Apr 30, 2012 #2

    HallsofIvy

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    If the curve is given by x= g(t) and y= f(t) then dx/dt= f'(t) and dy/dt= g'(t) so dx= f'(t)dt and dy= g'(t)dt. The integral for curve length is
    [tex]\int \sqrt{(dx)^2+ (dy)^2}= \int \sqrt{(f'(t)dt)^2+ (g'(t)dt)^2}= \int\sqrt{(f'(t))^2+ (g'(t))^2}dt[/tex]

    If the graph "overlaps itself" you only want to integrate over values of t that go over the path once. Choose some convenient point, [itex](x_0, y_0)[/itex], and find succesive solutions to [itex]f(t)= x_0[/itex], [itex]g(t)= y_0[/itex].
     
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