Parametric Representations of Circles and Ellipses

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Homework Help Overview

The discussion revolves around parametric representations of circles and ellipses, specifically focusing on the mathematical expressions and their interpretations in the complex plane and Cartesian coordinates.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the parametric representation of a circle defined by a complex equation and discuss the necessary transformations to derive its parameters. Questions arise regarding the correctness of the initial reasoning and the representation of an ellipse from its standard form.

Discussion Status

Some participants affirm the original poster's approach to part (a) while suggesting further adjustments to the equations. Guidance is offered on the parametric representation of an ellipse, with attempts to clarify the relationship between the standard form and its parametric equivalent.

Contextual Notes

Participants note the need for clarity on the representation of the ellipse and the implications of shifting the circle's center in the complex plane. There is an acknowledgment of the original poster's uncertainty regarding the ellipse, which may affect their understanding of the problem.

John O' Meara
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Sketch and represent parametrically the following: (a) [tex]\mid z+a+\iota b\mid =r \ \mbox { clockwise}\\[/tex], (b) ellipse [tex]4(x-1)^2 + 9(y+2)^2 =36 \[/tex].
Taking (a) first [tex]\mid z + a + \iota b \mid = r \mbox{- is the distance between the complex numbers }\ z=x+\iota y \ \mbox{ and } \ a + \iota b \ \mbox{ if the distance is always r, then we have } \ \sqrt{(x+a)^2 + (y+b)^2} = r \\[/tex]. This is a circle with center -a -ib and radius r, But the circle at the origin can be parametrically represented as [tex]r\exp{\iota t} \ 0 \leq \ t \ \leq 2\pi \\[/tex] but since t goes from [tex]0 \mbox{ to } 2\pi \\[/tex], clockwise it's equation is [tex]\exp{-\iota t} \\[/tex], therefore the circle is [tex]-a -\iota b + r\exp{-\iota t} = 0 \\[/tex]
Am I correct with (a)'s reasoning. I don't know how to do (b) as I know nothing about an ellipse. Thanks for the help.
 
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To get you started on b):

The equation for an ellipse centered at (0,0) is:

[tex]\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1[/tex]

Which has the parametric representation

[tex](a\cos{\theta},b\sin{\theta})[/tex]
 
For part (a) you are on the right track. Squaring both sides we get the equation for a circle with center (-a,-b) in the plane. Take the parametrization of a circle at the origin and perform horizontal and vertical shifts to it to get the parametrization of this particular circle.

The last equation is not correct. You should have the LHS in abs, and on the RHS there should be an r. squaring this equation, we just get the standard equation of circle.
 
Thanks for the reply
 
For the ellipse [tex]4(x-1)^2 + 9(y+2)^2 = 36 \mbox{. Therefore } \frac{(x-1)^2}{9} + \frac{(y+2)^2}{4} = 1 \\ = \frac{(x-1)^2}{3^2} + \frac{(y+2)^2}{2^2}[/tex]. This is an ellipse with semi-major axis and semi-minor axis of lengths 3 and 2 respectively whose center is at (1,-2). Therefore its equation is [tex]\mid 4x + 9 \iota y -1 +2 \iota\mid + 2\cos\theta +3\iota\sin\theta = 6 \ \mbox{ for} 0 \leq \theta \ \leq 2\pi \\[/tex].
About (a) do you mean [tex]\mid -a-\iota b +r\exp{-\iota t\mid =r[/tex]Thanks for helping.
 
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