- #1
John O' Meara
- 330
- 0
Sketch and represent parametrically the following: (a) [tex] \mid z+a+\iota b\mid =r \ \mbox { clockwise}\\ [/tex], (b) ellipse [tex] 4(x-1)^2 + 9(y+2)^2 =36 \ [/tex].
Taking (a) first [tex] \mid z + a + \iota b \mid = r \mbox{- is the distance between the complex numbers }\ z=x+\iota y \ \mbox{ and } \ a + \iota b \ \mbox{ if the distance is always r, then we have } \ \sqrt{(x+a)^2 + (y+b)^2} = r \\[/tex]. This is a circle with center -a -ib and radius r, But the circle at the origin can be parametrically represented as [tex] r\exp{\iota t} \ 0 \leq \ t \ \leq 2\pi \\[/tex] but since t goes from [tex] 0 \mbox{ to } 2\pi \\[/tex], clockwise it's equation is [tex] \exp{-\iota t} \\ [/tex], therefore the circle is [tex] -a -\iota b + r\exp{-\iota t} = 0 \\[/tex]
Am I correct with (a)'s reasoning. I don't know how to do (b) as I know nothing about an ellipse. Thanks for the help.
Taking (a) first [tex] \mid z + a + \iota b \mid = r \mbox{- is the distance between the complex numbers }\ z=x+\iota y \ \mbox{ and } \ a + \iota b \ \mbox{ if the distance is always r, then we have } \ \sqrt{(x+a)^2 + (y+b)^2} = r \\[/tex]. This is a circle with center -a -ib and radius r, But the circle at the origin can be parametrically represented as [tex] r\exp{\iota t} \ 0 \leq \ t \ \leq 2\pi \\[/tex] but since t goes from [tex] 0 \mbox{ to } 2\pi \\[/tex], clockwise it's equation is [tex] \exp{-\iota t} \\ [/tex], therefore the circle is [tex] -a -\iota b + r\exp{-\iota t} = 0 \\[/tex]
Am I correct with (a)'s reasoning. I don't know how to do (b) as I know nothing about an ellipse. Thanks for the help.