Partial Derivatives and The Chain Rule

AI Thread Summary
The discussion revolves around calculating the rates of change for the volume, surface area, and diagonal length of a box with changing dimensions. At a specific moment, the box's length, width, and height are given, along with their rates of change. The user successfully calculated the volume and surface area rates but struggled with the diagonal length. The correct approach involves using the formula for the diagonal and differentiating it with respect to time. The user confirmed that plugging in the original dimensions will yield the necessary value for the diagonal length calculation.
ktobrien
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Homework Statement


The length l, width w, and height h of a box change with time. At a certain instant the dimensions are l = 7 m and w = h = 9 m, and l and w are increasing at a rate of 6 m/s while h is decreasing at a rate of 3 m/s. At that instant find the rates at which the following quantities are changing.
(a) The Volume
(b) The Surface Area
(c) The Length of the Diagonal

Homework Equations


L2=l2+w2+h2

The Attempt at a Solution


I have already done part a and part b but I'm having trouble with c.
I tried to work it out and got 42m/s but this is incorrect. Some help please?
 
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42m/s is way too high. Just by gut feeling. How did you get that?
 
2l(dl/dt)+2w(dw/dt)+2h(dh/dt)
for A I got 675m^3/s
for B I got 312m^2/s
 
If L^2=l^2+w^2+h^2 then 2L(dL/dt)=2l(dl/dt)+2w(dw/dt)+2h(dh/dt). You want to solve for the dL/dt part. Don't forget to divide by the L. I didn't check the other ones. Do I need to?
 
No the other ones are right. I have already checked them. How do I get L to know what to divide by? Do I just plug in the original l w h to find L?
 
ktobrien said:
No the other ones are right. I have already checked them. How do I get L to know what to divide by? Do I just plug in the original l w h to find L?

Absolutely.
 
Thanks a lot. I figured it was something simple like that.
 
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