Partial Derivatives of Multivariable Functions

badtwistoffate
Messages
81
Reaction score
0
Ok i got this problem...
T(x,y,z,t)= -2xy^2+e^(-3z)cos(5x-.75t)
taking the partial derivative with respect to x first, so i break the problem apart with the left and right sign of the addition side

so i get...
-2y^2 for the left side and then am stubling on the right side, I am think just chain rule since e^(-3z) is constant right? so I get -sin(5x-.75t)5 from the right side.

any help
 
Physics news on Phys.org
So the final answer for \partial T/\partial x is what according to you?
 
its -2y^2-e^(-3z)*sin(5x-.75t)5 I THINK, butttt... i have a voyage 200 near me and when i check it, its giving me a error and I don't trust myself enough to think its right...
 
Last edited:
That's the correct answer. What's a voyage 200?
 
its a TI calculator that does alot.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top