- #1
stunner5000pt
- 1,443
- 4
Here is one of them - i posted it in another thread and i am getting help in there https://www.physicsforums.com/showthread.php?t=91781
this is another of my problems
Show that if C is a piecewise continuously differentiable closed curve bounding D then the problem
\nabla^2 u= -F(x,y) \ in\ D
u = f \ on \ C_{1}
\frac{\partial u}{\partial n} + \alpha u = 0 \ on \ C_{2}
where C1 is a part of C and C2 the remainder and where alpha is a positive constant, has at most one solution.
now i know that \nabla^2 u = \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = -F(x,y)
now I am not quite sure how to connect the C1 part to C2 part...
would it be something liek C= C1 + C2?
but how would one go about showing that this has at most ONE solution?? I m not quite sure how to start ... Please help
another one
Show that the problem
\frac{\partial}{\partial x} (e^x \frac{\partial u}{\partial x} + \frac{\partial}{\partial y} (e^y \frac{\partial u}{\partial y} = 0 \ for \ x^2+y^2 < 1
u = x^2 for x^2 + y^2 = 1
has at most one solution
Hint Use the divergence theorem to derive an energy identity
Perhaps i don't remember a theorem i should have learned in ap revious class... or i am not familiar with it but what would i use the divergence theorem here?
i eman i can get it down to this
e^x \frac{\partial}{\partial x} (u + \frac{\partial u}{\partial x}) + e^y \frac{\partial}{\partial y} (u + \frac{\partial u}{\partial y}) = 0
but hereafter i am stuck, please do advise!
Thank you!
this is another of my problems
Show that if C is a piecewise continuously differentiable closed curve bounding D then the problem
\nabla^2 u= -F(x,y) \ in\ D
u = f \ on \ C_{1}
\frac{\partial u}{\partial n} + \alpha u = 0 \ on \ C_{2}
where C1 is a part of C and C2 the remainder and where alpha is a positive constant, has at most one solution.
now i know that \nabla^2 u = \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = -F(x,y)
now I am not quite sure how to connect the C1 part to C2 part...
would it be something liek C= C1 + C2?
but how would one go about showing that this has at most ONE solution?? I m not quite sure how to start ... Please help
another one
Show that the problem
\frac{\partial}{\partial x} (e^x \frac{\partial u}{\partial x} + \frac{\partial}{\partial y} (e^y \frac{\partial u}{\partial y} = 0 \ for \ x^2+y^2 < 1
u = x^2 for x^2 + y^2 = 1
has at most one solution
Hint Use the divergence theorem to derive an energy identity
Perhaps i don't remember a theorem i should have learned in ap revious class... or i am not familiar with it but what would i use the divergence theorem here?
i eman i can get it down to this
e^x \frac{\partial}{\partial x} (u + \frac{\partial u}{\partial x}) + e^y \frac{\partial}{\partial y} (u + \frac{\partial u}{\partial y}) = 0
but hereafter i am stuck, please do advise!
Thank you!
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