Partial differential equations, symmetries, invariants, conservations,

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SUMMARY

The discussion focuses on the application of adjoint equations and conservation laws in the context of partial differential equations (PDEs). Key components include the Lagrange functional, the matrix representation of the adjoint operator, and the formulation of conservation laws through integrals. The equations presented, such as $$F_1=u_{xx}-u^2v-u_t$$ and $$F_2=-v_{xx}-v^2u-v_t$$, are critical for deriving the necessary conditions for the adjoint equation. The conservation law theorem is expressed as $$I(v)=\int_0^1 d\lambda\int dx$$ under specific conditions for the vector function.

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Homework Statement
find the invariant of system of real shrodinger-like system of pd equations with independent variables x,t and dependent u, v
Relevant Equations
u_t=u_{xx} - u^2 v
v_t =-v_{xx}-v^2 u
I know the method is involving adjoint equation, lagrange functional and conserwation laws but i dont know how to do it, please help! I know something like this: that we must split our function into two F=(F_1,F_2), also u=(u_1,u_2) and v=(v_1,v_2) and we must calculate adjoint equation F* and bcs of the vector function F the F'* is a matrix
F*'=\begin{bmatrix}
F_1_u_1'* & F_2_u_1'*\\
F_1_u_2'* & F_2_u_2'
\end{bmatrix}
and the quation is F'*v=0
and the conservation law theorem is I(v)=\int_0^1 d\lambda\int <v(\lambda u_1,\lambda u_2 | u_1,u_2)> dx under condition v=grad I(v) and there is second condition for v : v_u= v_u*
 
Last edited:
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Hello and :welcome: !

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##\ ##
 
is soemthing like $$\mathcal{L}(u,v)=<u| F>$$ and $$u=(u_1,u_2)\quad v=(v_1,v_2)\quad F=(F_1,F_2)$$ and
$$F_1=u_{xx}-u^2v-u_t \quad F_2=-v_{xx}-v^2u-v_t$$ and
$$\frac{\delta \mathcal{L}}{\delta u}=(\frac{\delta\mathcal{L}}{\delta u_1},\frac{\delta\mathcal{L}}{\delta u_2}) =F^{\ast}(u)\cdot v=0, where
$$
and
$$
F^{\ast}_u=
$$
is a matrix 2x2 with entries
$$
F^{\ast}_{1_{u_1}}, \quad F^{\ast}_{2_{u_1}}, \quad F^{\ast}_{1_{u_2}}, \quad F^{\ast}_{2_{u_2}}
$$
and for conservation law
$$
\int_0^1 d\lambda \int <v(\lambda u_1,\lambda u_2)| (u_1,u_2)> dx = I(u)
$$
when
$$
v_u=v_u^{\ast} \Rightarrow v=grad I(u)
$$
 
Last edited:

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